If I have the equation $9x^2-4y^2-72x=0 $ and I know that is a hyperbola, how would I find the standard form for this equation? I'm not sure how to convert this equation to the standard form of a hyperbola.
$\endgroup$1 Answer
$\begingroup$$9(x^2-8x) - 4y^2 = 0 \to 9(x-4)^2 - 4y^2 = 12^2 \to \dfrac{(x-4)^2}{4^2} - \dfrac{y^2}{6^2} = 1$.
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