Matrix multiplication question of 2 3x1 vectors

$\begingroup$

I'm not sure how the matrix multiplication at the second image works is it a typo or is my understanding of matrix multiplication flawed.Full solution

Part i am confused about

$\endgroup$ 1

1 Answer

$\begingroup$

The cross product is defined as follows:

$$\begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix}\times \begin{bmatrix} c_1 \\ c_2 \\ c_3 \end{bmatrix} = \begin{bmatrix} b_2c_3-b_3c_2 \\ -(b_1c_3-b_3c_1) \\ b_1c_2-b_2c_1\end{bmatrix}$$

It take in two vectors and returns a vector that is perpendicular to the plane generated by the first two vectors.

The dot product is defined as follows:

$$\begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix}\cdot \begin{bmatrix} c_1 \\ c_2 \\ c_3 \end{bmatrix} = b_1c_1+b_2c_2+b_3c_3$$

Hence,

\begin{align}&\begin{pmatrix} a_1 \\ a_2 \\ a_3 \end{pmatrix}\cdot \begin{bmatrix} \begin{pmatrix} b_1 \\ b_2 \\ b_3 \end{pmatrix} \times \begin{pmatrix} x_1+y_1 \\ x_2+y_2 \\ x_3+y_3 \end{pmatrix}\end{bmatrix}\\&= \begin{pmatrix} a_1 \\ a_2 \\ a_3 \end{pmatrix}\cdot \begin{bmatrix} \begin{pmatrix} b_2(x_3+y_3)-b_3(x_2+y_2) \\ -b_1(x_3+y_3)+b_3(x_1+y_1) \\ b_1(x_2+y_2)-b_2(x_1+y_1) \end{pmatrix} \end{bmatrix} \\&=a_1 (b_2(x_3+y_3)-b_3(x_2+y_2))+a_2(-b_1(x_3+y_3)+b_3(x_1+y_1))+a_3(b_1(x_2+y_2)-b_2(x_1+y_1))\end{align}

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

You Might Also Like