I have having an issue identifying the inner function of this function:
$$f(g(x))=\frac{1}{\sqrt{x+1}}$$
I "need" to take the derivative of it; hence I have to identify the inner function. My current thinking is that the inner function is $\sqrt{x+1}$, and outer would be $\frac{1}{x}$.
Outer
$$\frac{1}{x}$$
Inner
$$\sqrt{x+1}$$
Is my answer to the identification of the outside and inner functions correct?
$\endgroup$ 71 Answer
$\begingroup$Those are two possible solutions for the inner and outer functions, however, if you are to apply the chain rule, I would suggest just using $(x+1)^\frac{-1}{2}$ for your chain rule
$\endgroup$