I am to find the quotient using synthetic division: $\frac{x+1}{x-i}$
The solution is provided as $1+\frac{1+i}{x-i}$
I get $2+i$.
My working:
$$\begin{array} & i & | & 1 & 1 \end{array}$$
Pull down the 1 then multiply by i
sum 1 and i
$1+(1+i)$ = $2+i$
How can I arrive at $1+\frac{1+i}{x-i}$?
$\endgroup$ 11 Answer
$\begingroup$Your work is already correct (except for the step where you did $1+(1+i)$). Remember that the $(1+i)$ at the end of the synthetic division is the remainder, so what you ended up with is indeed $1+\frac{1+i}{x-i}$. You should not have added $(1+i)$ and $1$ together.
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