There is a $1\times 1$ unit-square with diagonals from each corner. This square contains $8$ total triangles. Now, if we expanded to an $n\times n$ square, which is comprised of these unit-squares, how many total triangles are there?
I tried to break this problem down. For a $2\times 2$ square, we have $4$ smaller unit squares, where each contain two diagonal lines. I counted the triangles by hand and found out that there are $44$ total triangles. Is there a formula for an $n\times n$ square?
$\endgroup$ 2 Reset to default
